x(x+3)=x^2-2(x-5)

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Solution for x(x+3)=x^2-2(x-5) equation:


Simplifying
x(x + 3) = x2 + -2(x + -5)

Reorder the terms:
x(3 + x) = x2 + -2(x + -5)
(3 * x + x * x) = x2 + -2(x + -5)
(3x + x2) = x2 + -2(x + -5)

Reorder the terms:
3x + x2 = x2 + -2(-5 + x)
3x + x2 = x2 + (-5 * -2 + x * -2)
3x + x2 = x2 + (10 + -2x)

Reorder the terms:
3x + x2 = 10 + -2x + x2

Add '-1x2' to each side of the equation.
3x + x2 + -1x2 = 10 + -2x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
3x + 0 = 10 + -2x + x2 + -1x2
3x = 10 + -2x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
3x = 10 + -2x + 0
3x = 10 + -2x

Solving
3x = 10 + -2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2x' to each side of the equation.
3x + 2x = 10 + -2x + 2x

Combine like terms: 3x + 2x = 5x
5x = 10 + -2x + 2x

Combine like terms: -2x + 2x = 0
5x = 10 + 0
5x = 10

Divide each side by '5'.
x = 2

Simplifying
x = 2

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